是的,git中說(shuō)的repo 就是 Repository 的縮寫(xiě)
你好,遇到了同樣的問(wèn)題,有解決方案嗎?
"...your current branch is behind its remote counterpart..."
你的分支版本落后遠(yuǎn)程相應(yīng)的版本,如果樓上所說(shuō),git pull 同步遠(yuǎn)程,再提交
答案是在 _config.yml
里面。
但是這個(gè)問(wèn)題不該去看主題的文檔么?
Ubuntu 和 centos 這兩種發(fā)行版都可以添加軟件倉(cāng)庫(kù)源,不過(guò)類(lèi)型不一樣,不能直接調(diào)換使用。
Ubuntu 源于 Debian,使用 deb 包格式。
而 centos 與 RedHat 相近,使用 yum (或叫 EPEL) 包格式。
雖然兩種格式不兼容,不過(guò)對(duì)大部分 GNU 或其它開(kāi)源軟件來(lái)說(shuō),都可以找到 deb 或 yum 源。
new
is not an operator
!In c++, new
and operator
are both keywords. new int(x)
is a(n) (new-)expression. operator new is a function. new operator in your title is new-expression indeed. new-expression will invoke oeprator new function.
placement new的作用就是在operator new分配好的內(nèi)存上執(zhí)行對(duì)象的構(gòu)造,
Yes, that's true. To help you understand, here is a sample:
char* ptr = new char[sizeof(T)]; // ptr use a new-expression(newchar [sizeof(T)] to allocate memory, char is guaranteed to be sizeof 1
T* tptr = new(ptr) T; // Here is placement new
In a nutshell, placement new will use already allocated memory to construct the object. Where is the already allocated memory from? Either from new expression(free store) or allocated from activation record
like int buffer[10]
, both ok.
那么new operator使用了operator new來(lái)申請(qǐng)內(nèi)存之后是使用了placement new嗎?如果沒(méi)有話(huà)是怎么構(gòu)造的呢?和placement new有關(guān)系嗎?
Above is my answer to your questions
BTW, from the case int buffer[10]
, we can see pre-new-expression is not a must for placement new(however, note that placement new itself is a new-expression, which will invoke operator new function because all it does is just construct here). If your question is "will placement new always be after operator new/new-expression", it will be a good question.
One year ago, I was confused about how to combine operator new with the constructor then asked a question, FrankHB answered my question: https://tieba.baidu.com/p/508... Now, look back to this question, it is a X-Y question, what really confused me was how does new expression invoke constructor, so it is not related to placement new. Hope it will also inspire you.
所以我認(rèn)為或許自己和您一年前的疑問(wèn)相似,內(nèi)存申請(qǐng)和構(gòu)造函數(shù)這兩個(gè)過(guò)程是如何結(jié)合的呢?
the wordcombination
(結(jié)合) is not properly now(I also make such mistake as said above), let me re-organize my wording:
new expression does two things:
You and I(one year ago) are both confused about how does compiler initialize the object(via constructor or else) after allocating. Yes, I mentioned compiler, because C++ standard guarantee new will do the two things, but didn't how to, so, its compiler's work. So, it is not c++'s work, just compiler's. Now, we can see the assembly:
struct Foo
{
Foo(int i) {}
};
int main()
{
auto *a = new Foo(1);
}
-O0:
Foo::Foo(int):
push rbp
mov rbp, rsp
mov QWORD PTR [rbp-8], rdi
mov DWORD PTR [rbp-12], esi
pop rbp
ret
main:
push rbp
mov rbp, rsp
push rbx
sub rsp, 24
mov edi, 1
call operator new(unsigned long)
mov rbx, rax
mov esi, 1
mov rdi, rbx
call Foo::Foo(int)
mov QWORD PTR [rbp-24], rbx
mov eax, 0
add rsp, 24
pop rbx
pop rbp
ret
codes related the new expression is follows: a
mov edi, 1
call operator new(unsigned long)
mov rbx, rax
mov esi, 1
mov rdi, rbx
call Foo::Foo(int)
mov QWORD PTR [rbp-24], rbx
Now, it is clear enough, right? assemble calls two procedures, oeprator new and Foo::Foo(int)
So, your question is how the two combined?
Podfile和Podfile.lock放到遠(yuǎn)程就行了,添加一個(gè).gitignote文件把不需要的東西不用上傳到git上面 http://www.jianshu.com/p/82e1...
網(wǎng)關(guān)不通,則外網(wǎng)肯定不通,你可以嘗試下能DHCP獲取地址嗎?
1.修改端口
2.vagrant
3.docker
ln -sf /usr/share/zoneinfo/Asia/Shanghai /etc/localtime CST-8
D:\Program Files\Git\usr\bin
1/3+1/3請(qǐng)用10位小數(shù)表示。
。。。參見(jiàn)鏈接:https://blog.lab99.org/post/d...
這里有非常詳盡的配置布驟, 逐一執(zhí)行就好了.
其中建虛擬環(huán)境時(shí)要指定python版本.
virtualenv -p python3 envname
let check = (data) => {
let arr = []
for (let k in data) {
if (arr.indexOf(data[k]) === -1) {
arr.push(data[k])
} else {
return true
}
}
}
let data = {
"bqw": "123",
"bfr": "1234",
"asq": "1235",
"ase": "1236",
"bd": "1237",
"bua": "123",
"bgg": "1238",
"bug": "1239"
}
if (check(data)) {
alert('重復(fù)')
}
// true
大概就是一個(gè)數(shù)組臨時(shí)保存object的值,indexof來(lái)判斷下一值在數(shù)組中是否存在,存在返回true
rm -rf /var/lib/docker 然后重啟docker確實(shí)可以解決這個(gè)問(wèn)題,但是鏡像全部沒(méi)有了
1.確保你的B分支代碼都已經(jīng)提交
2.git checkout A
3.git pull origin A
4.git merge B
5.解決沖突
6.提交
git add .
git commit -am'xxx'
git push origin A
4 的意思是說(shuō)獲取到sessionid之后再刪除 然后再訪(fǎng)問(wèn) 得不到sessionid嗎?
tomcat應(yīng)該是判斷請(qǐng)求中如果有sessionid就繼續(xù)會(huì)話(huà) , 沒(méi)有的話(huà)就new 一個(gè)新的session 返回sessionid吧
在瀏覽器把包含sessionid的cookie刪了 , 服務(wù)器應(yīng)該會(huì)認(rèn)為是一個(gè)新的會(huì)話(huà) 返回新的sessionid 和路徑?jīng)]有關(guān)系
北大青鳥(niǎo)APTECH成立于1999年。依托北京大學(xué)優(yōu)質(zhì)雄厚的教育資源和背景,秉承“教育改變生活”的發(fā)展理念,致力于培養(yǎng)中國(guó)IT技能型緊缺人才,是大數(shù)據(jù)專(zhuān)業(yè)的國(guó)家
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中公教育集團(tuán)創(chuàng)建于1999年,經(jīng)過(guò)二十年潛心發(fā)展,已由一家北大畢業(yè)生自主創(chuàng)業(yè)的信息技術(shù)與教育服務(wù)機(jī)構(gòu),發(fā)展為教育服務(wù)業(yè)的綜合性企業(yè)集團(tuán),成為集合面授教學(xué)培訓(xùn)、網(wǎng)
達(dá)內(nèi)教育集團(tuán)成立于2002年,是一家由留學(xué)海歸創(chuàng)辦的高端職業(yè)教育培訓(xùn)機(jī)構(gòu),是中國(guó)一站式人才培養(yǎng)平臺(tái)、一站式人才輸送平臺(tái)。2014年4月3日在美國(guó)成功上市,融資1
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